Answer
$f^{-1}(x) = \log_4 \frac{x}{3}$
Work Step by Step
$f(x) = 3(4^{x})$
Let $f(x) = y$
$y = 3(4^{x})$
Swap the $x$ and $y$ variable to find the inverse:
$x = 3(4^{y})$
$\frac{x}{3} = 4^{y}$
$y = \log_4 \frac{x}{3}$
$f^{-1}(x) = \log_4 \frac{x}{3}$