Answer
$B^{-1}(t) = \ln t$
Work Step by Step
$B(t) = e^{t}$
Let $B(t) = y$
$y = e^{t}$
Swap the $t$ and $y$ variables then solve for $y$ to find the inverse:
$t = e^{y}$
$y = \ln t$
$B^{-1}(t) = \ln t.$
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