Answer
$g^{-1}(x) = e^{x}$
Work Step by Step
$g(x) = \ln x$
Let $g(x) = y$
$y = \ln x$
Swap the $x$ and $y$ variable to find the inverse:
$x = \log_e y$
$y = e^{x}$
$g^{-1}(x) = e^{x}$
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