Answer
$h^{-1}(t) = 9^{t}$
Work Step by Step
$h(t) = \log_9 t$
Let $h(t) = y$
$y = \log_9 t$
Swap the $t$ and $y$ variable to find the inverse:
$t = \log_9 y$
$y =9^{t}$
$h^{-1}(t) = 9^{t}$
Intermediate Algebra: Connecting Concepts through Application
by Clark, Mark; Anfinson, Cynthia
Published by
Brooks Cole
ISBN 10:
0-53449-636-9
ISBN 13:
978-0-53449-636-4
Chapter 6 - Logarithmic Functions - 6.2 Logarithmic Functions - 6.2 Exercises - Page 504: 92
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