Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 6 - Logarithmic Functions - 6.2 Logarithmic Functions - 6.2 Exercises - Page 504: 52

Answer

$\approx -0.346$

Work Step by Step

The base of the logarithm is not $10$, therefore you require the change of base formula before evaluating: $= \log_{17} (0.375)$ $= \frac{\log 0.375}{\log 17}$ $= -0.34618...$ $\approx -0.346$
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