Answer
$= -4$
Work Step by Step
$ \log_2 (\frac{1}{16})$
$= \log_2 16^{-1}$
$= \log_2 2^{-4}$
$= -4$
Intermediate Algebra: Connecting Concepts through Application
by Clark, Mark; Anfinson, Cynthia
Published by
Brooks Cole
ISBN 10:
0-53449-636-9
ISBN 13:
978-0-53449-636-4
Chapter 6 - Logarithmic Functions - 6.2 Logarithmic Functions - 6.2 Exercises - Page 504: 16
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