Answer
$g^{-1}(t) = \log_2 t$
Work Step by Step
$g(t) = 2^{t}$
Let $g(t) = y$
$y = 2^{t}$
Swap the $t$ and $y$ variables then solve for $y$ to find the inverse:
$t = 2^{y}$
$y = \log_2 t$
$g^{-1}(t) = \log_2 t.$
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