Answer
$h^{-1}(c) = \log c$
Work Step by Step
$h(c) = 10^{c}$
Let $h(c) = y$
$y = 10^{c}$
Swap the $c$ and $y$ variables then solve for $y$ to find the inverse:
$c = 10^{y}$
$y = \log_{10} c$
$y = \log c$
$h^{-1}(c) = \log c$
Intermediate Algebra: Connecting Concepts through Application
by Clark, Mark; Anfinson, Cynthia
Published by
Brooks Cole
ISBN 10:
0-53449-636-9
ISBN 13:
978-0-53449-636-4
Chapter 6 - Logarithmic Functions - 6.2 Logarithmic Functions - 6.2 Exercises - Page 504: 85
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