Chapter 9 - Section 9.8 - Exponential and Logarithmic Equations and Problem Solving - Exercise Set - Page 591: 66

$-\dfrac{13}{4}$

Using the given values of the variables ($x=-2,$ $y=0,$ and $z=3$), the given expression, $ \dfrac{4y-3x+z}{2x+y} ,$ evaluates to \begin{array}{l}\require{cancel} \dfrac{4(0)-3(-2)+3}{2(-2)+0} \\\\= \dfrac{4+6+3}{-4+0} \\\\= \dfrac{13}{-4} \\\\= -\dfrac{13}{4} .\end{array}