Chapter 9 - Section 9.8 - Exponential and Logarithmic Equations and Problem Solving - Exercise Set - Page 591: 65

$\dfrac{17}{4}$

Using the given values of the variables ($x=-2,$ $y=0,$ and $z=3$), the given expression, $ \dfrac{3z-4x+y}{x+2z} ,$ evaluates to \begin{array}{l}\require{cancel} \dfrac{3(3)-4(-2)+0}{-2+2(3)} \\\\= \dfrac{9+8+0}{-2+6} \\\\= \dfrac{17}{4} .\end{array}