Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Section 9.8 - Exponential and Logarithmic Equations and Problem Solving - Exercise Set - Page 591: 49

Answer

$$t=8.84 \ years$$

Work Step by Step

We now consider a 1000 dollar investment with 8 percent interest compounded semi annually. $$2000=1000(1+(.08/2))^{2t}$$ This gives: $$2t=log_{1.04}(2)$$ $$t=8.84 \ years$$
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