Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Section 9.8 - Exponential and Logarithmic Equations and Problem Solving - Exercise Set - Page 591: 48

Answer

$$t=1.3 \ years$$

Work Step by Step

We now consider a 1500 dollar investment with 10 percent interest compounded semi annually. $$1700=1500(1+(.1/2))^{2t}$$ This gives: $$2t=log_{1.05}(17/15)$$ $$t=1.3 \ years$$
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