Answer
$-\dfrac{5}{3}$
Work Step by Step
Using the given values of the variables ($x=-2,$ $y=0,$ and $z=3$), the given expression, $
\dfrac{x^2-y+2z}{3x}
,$ evaluates to
\begin{array}{l}\require{cancel}
\dfrac{(-2)^2-(0)+2(3)}{3(-2)}
\\\\=
\dfrac{4-0+6}{-6}
\\\\=
\dfrac{10}{-6}
\\\\=
-\dfrac{\cancel{2}\cdot5}{\cancel{2}\cdot3}
\\\\=
-\dfrac{5}{3}
.\end{array}
