Answer
$(2x+1-z)(2x+1+z)$
Work Step by Step
Using factoring techniques, then,
\begin{array}{l}
4x^2+4x+1-z^2
\\=
(4x^2+4x+1)-z^2
\\=
(2x+1)^2-z^2
\\=
[(2x+1)-z][(2x+1)+z]
\\=
(2x+1-z)(2x+1+z)
.\end{array}
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 5 - Section 5.7 - Factoring by Special Products - Exercise Set - Page 309: 51
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