Answer
$(3x+y-5)(3x+y+5)$
Work Step by Step
Using $a^2-b^2=(a+b)(a-b)$ or the factoring of the difference of two squares, then,
\begin{array}{l}
(3x+y)^2-25
\\=
[(3x+y)-5][(3x+y)+5]
\\=
(3x+y-5)(3x+y+5)
.\end{array}
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 5 - Section 5.7 - Factoring by Special Products - Exercise Set - Page 309: 22
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