Answer
See graph
Work Step by Step
$$y=4x^2-40x+105$$
$$\frac{y-105}{4}=x^2-10x$$
Complete the square.
$$\frac{y-105}{4}+25=x^2-10x+25$$
$$y=4(x-5)^2+5$$
The vertex is (5,5).
Substitute x-values to find their corresponding y-values.
$$y=4(4-5)^2+5$$
$$y=9$$
$$(4,9)$$.
$$y=4(6-5)^2+5$$
$$y=9$$
$$(6,9)$$
Plot these points on a graph and connect with a smooth curve.
