Answer
See graph
Work Step by Step
$$y=5x^2-20x+16$$
$$\frac{y-16}{5}=x^2-4x$$
Complete the square.
$$\frac{y-16}{5}+4=x^2-4x+4$$
$$\frac{y-16}{5}+4=(x-2)^2$$
$$y-16+20=5(x-2)^2$$
$$y=5(x-2)^2-4$$
This is a parabola with vertex (2,-4). It opens upwards.
Substitute x-values to find their corresponding y-values.
$$y=5(2-2)^2-4$$
$$y=-4$$
$$(2,-4)$$
$$y=5(3-2)^2-4$$
$$y=1$$
$$(3,1)$$
Plot these points on a graph and connect with a smooth curve.
