Answer
See graph
Work Step by Step
$$x=-2y^2-4y$$
$$x=-2(y^2+2y)$$
Complete the square.
$$x=-2(y^2+2y+1)$$
$$x-2=-2(y+1)^2$$
$$x=-2(y+1)^2+2$$
The vertex is (2,-1) and the parabola opens left.
Substitute 0 for x to find the corresponding y-values.
$$0=-2(y+1)^2+2$$
$$1=(y+1)^2$$
$$0=y$$
$$(0,0)$$
$$-1=y+1$$
$$y=-2$$
$$(0,-2)$$
Plot these points on a graph and connect with a smooth curve.
