Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 10 - Section 10.1 - The Parabola and the Circle - Exercise Set - Page 610: 35

Answer

See graph

Work Step by Step

$$x^2+y^2-4x-8y-2=0$$ $$x^2+y^2-4x-8y=2$$ $$x^2-4x+4+y^2-8y+16=2+4+16$$ $$(x-2)^2+(y-4)^2=22$$ The center is (2,4) and the radius is $\sqrt{22}$. Points to plot are: $$(2+\sqrt{22},4)$$ $$(2-\sqrt{22},4)$$ $$(2,4+\sqrt{22})$$ $$(2,4-\sqrt{22})$$ Approximate these values with a calculator, plot these points and connect with a circle.
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