Answer
See graph
Work Step by Step
$$x=y^2+8y-4$$
$$x+4=y^2+8y$$
Complete the square.
$$x+4+16=y^2+8y+16$$
$$x=(y+4)^2-20$$
This is a parabola with vertex (-20,-4) that opens to the right.
Substitute values for x to find their corresponding y-values.
$$5=(y+4)^2-20$$
$$25=(y+4)^2$$
$$5=y+4$$
$$y=1$$
$$(5,1)$$
$$-5=y+4$$
$$-9=y$$
$$(5,-9)$$
Connect these points with a smooth curve.
