Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 10 - Section 10.1 - The Parabola and the Circle - Exercise Set - Page 610: 59

Answer

See graph

Work Step by Step

$$x=-(y-1)^2$$ The vertex is (0,1); we know this because the equation is in vertex form. The parabola opens to the left. Substitute values for x to find their corresponding y-values. $$1=-(y-1)^2$$ $$1=-(y-1)$$ $$-1=y-1$$ $$y=0$$ $$-1=-(y-1)$$ $$1=y-1$$ $$y=2$$ $$(-1,0)$$ $$(-1,2)$$
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