Answer
See graph
Work Step by Step
$$y=x^2-2x-15$$
$$y=(x-5)(x+3)$$
$$x=5,-3$$
These are the zeroes of the equation. The x-coordinate of the vertex is in between these two zeroes.
$$x=1$$
$$y=(1)^2-2(1)-15$$
$$y=-16$$
$$(1,-16)$$
Connect these points with a smooth curve.
