Answer
$a_n=\frac{1}{4}\times\frac{1}{4}^{n-1}=\frac{1}{4}^{n}$
Work Step by Step
The general term in a geometric sequence is:
$a_n=a_1\times r^{n-1}$
Here, $a_1=\frac{1}{4}$
We can find the common ratio by dividing two subsequent terms:
$r=\frac{a_2}{a_1}=\frac{\frac{1}{16}}{\frac{1}{4}}=\frac{4}{16}=\frac{1}{4}$
The general term is:
$a_n=\frac{1}{4}\times\frac{1}{4}^{n-1}=\frac{1}{4}^{n}$
