Answer
$2\log_a w-2\log_ax+\log_ay$
Work Step by Step
Using the properties of logarithms, the given expression, $
\log_a(w^2x^{-2}y)
,$ is equivalent to
\begin{array}{l}\require{cancel}
\log_a w^2+\log_ax^{-2}+\log_ay
\\\\=
2\log_a w-2\log_ax+\log_ay
.\end{array}