Answer
$\dfrac{1}{2}\log_{10} y$
Work Step by Step
Using $\log_b x^a=a\log_b x$ (or the logarithm of a power), the given logarithmic equation, $
\log_{10} y^{1/2}
,$ is equivalent to
\begin{array}{l}\require{cancel}
\dfrac{1}{2}\log_{10} y
.\end{array}