Answer
$\log_a13$
Work Step by Step
Using $\log_b x-\log_b y=\log_b \dfrac{x}{y}$ (or the logarithm of a quotient), the given logarithmic equation, $
\log_a 26-\log_a 2
,$ is equivalent to
\begin{array}{l}\require{cancel}
\log_a \dfrac{26}{2}
\\\\
\log_a13
.\end{array}