Answer
$(f+g)(x)=3x \rightarrow$ $D=(-\infty,+\infty)$
$(f-g)(x)=-x \rightarrow$ $D=(-\infty,+\infty)$
$(f.g)(x)=2x^{2} \rightarrow$ $D=(-\infty,+\infty)$
$(\frac{f}{g})(x)=\frac{1}{2} \rightarrow$ $D=(-\infty,+\infty)$
Work Step by Step
We are given $f(x)=x$ and $g(x)=2x$
$(f+g)(x)=3x \rightarrow$ the domain is $(-\infty,+\infty)$
$(f-g)(x)=-x \rightarrow$ the domain is $(-\infty,+\infty)$
$(f.g)(x)=2x^{2} \rightarrow$ the domain is $(-\infty,+\infty)$
$(\frac{f}{g})(x)=\frac{1}{2} \rightarrow$ the domain is $(-\infty,+\infty)$