Answer
$=x^2+16x+64$
$=(x+8)^2$
Work Step by Step
The given expression is
$=x^2+16x$
Find the value of $(\frac{b}{2})^2$.
Substitute $16$ for $b$.
$=(\frac{16}{2})^2$
Simplify.
$=(8)^2$
$=64$
Add $64$ to the given expression.
$=x^2+16x+64$
Write the the polynomial as $a^2+2ab+b^2$.
$=x^2+2(x)(8)+(8)^2$
Use perfect square trinomial pattern
$a^2+2ab+b^2=(a+b)^2$
We have $a=x$ and $b=8$.
$=(x+8)^2$