Answer
$(v-4)(v-1)$.
Work Step by Step
The given polynomial is
$=v^2-5v+4$
Standard form is $x^2+bx+c$.
We have $b=-5$ and $c=4$.
$b$ is negative and $c$ is positive.
Factor pair of $4$, whose sum is $-5$:-
$-4,-1$
The values of $p$ and $q$ are $-4$ and $-1$.
Hence, the factor of the polynomial is $(v+p)(v+q)=(v-4)(v-1)$.
Check:-
$=(v-4)(v-1)$
$=v^2-v-4v+4$
$=v^2-5v+4$
True.
