Answer
The solutions are $v=-13$ and $v=2$.
Work Step by Step
To factor the polynomial $v^{2}+bv+c$ to $(v+p)$ and $(v+q)$, we need to have $p+q=b$ and $pq=c$.
In this case, $b=11$ and $c=-26$.
$\implies p=13$ and $q=-2$.
Then, $v^{2}+11v-26=(v+13)(v-2)$
$v^{2}+11v-26=0\implies (v+13)(v-2)=0$
Using zero-product property, we have
$v+13=0$ or $v-2=0$
$\implies v=-13$ or $v=2$
The solutions are $v=-13$ and $v=2$.
