Answer
$(t-8)(t+2)$.
Work Step by Step
The given polynomial is
$=-6t-16+t^2$
$=t^2-6t-16$
Standard form is $x^2+bx+c$.
We have $b=-6$ and $c=-16$.
$b$ and $c$ is negative.
Factor pair of $-16$, whose sum is $-6$:-
$-8,2$
The values of $p$ and $q$ are $-8$ and $2$.
Hence, the factor of the polynomial is $(t+p)(t+q)=(t-8)(t+2)$.
Check:-
$=(t-8)(t+2)$
$=t^2+2t-8t-16$
$=t^2-6t-16$
True.
