Answer
$(d-3)(d-2)$.
Work Step by Step
The given polynomial is
$=d^2-5d+6$
Standard form is $x^2+bx+c$.
We have $b=-5$ and $c=6$.
$b$ is negative and $c$ is positive.
Factor pair of $6$, whose sum is $-5$:-
$-3,-2$
The values of $p$ and $q$ are $-3$ and $-2$.
Hence, the factor of the polynomial is $(d+p)(d+q)=(d-3)(d-2)$.
Check:-
$=(d-3)(d-2)$
$=d^2-2d-3d+6$
$=d^2-5d+6$
True.
