Answer
$(h-3)(h+9)$.
Work Step by Step
The given polynomial is
$=h^2+6h-27$
Standard form is $x^2+bx+c$.
We have $b=6$ and $c=-27$.
$b$ is positive and $c$ is negative.
Factor pair of $-27$, whose sum is $6$:-
$-3,9$
The values of $p$ and $q$ are $-3$ and $9$.
Hence, the factor of the polynomial is $(h+p)(h+q)=(h-3)(h+9)$.
Check:-
$=(h-3)(h+9)$
$=h^2+9h-3h-27$
$=h^2+6h-27$
True.
