Answer
$(k-6)(k-4)$.
Work Step by Step
The given polynomial is
$=k^2-10k+24$
Standard form is $x^2+bx+c$.
We have $b=-10$ and $c=24$.
$b$ is negative and $c$ is positive.
Factor pair of $24$, whose sum is $-10$:-
$-6,-4$
The values of $p$ and $q$ are $-6$ and $-4$.
Hence, the factor of the polynomial is $(k+p)(k+q)=(k-6)(k-4)$.
Check:-
$=(k-6)(k-4)$
$=k^2-4d-6d+24$
$=k^2-10k+24$
True.
