Answer
$(z-2)(z+9)$.
Work Step by Step
The given polynomial is
$=z^2+7z-18$
Standard form is $x^2+bx+c$.
We have $b=7$ and $c=-18$.
$b$ is positive and $c$ is negative.
Factor pair of $-18$, whose sum is $7$:-
$-2,9$
The values of $p$ and $q$ are $-2$ and $9$.
Hence, the factor of the polynomial is $(z+p)(z+q)=(z-2)(z+9)$.
Check:-
$=(z-2)(z+9)$
$=z^2+9x-2x-18$
$=z^2+7z-18$
True.
