Answer
$(y-6)(y+8)$.
Work Step by Step
The given polynomial is
$=y^2+2y-48$
Standard form is $x^2+bx+c$.
We have $b=2$ and $c=-48$.
$b$ is positive and $c$ is negative.
Factor pair of $-48$, whose sum is $2$:-
$-6,8$
The values of $p$ and $q$ are $-6$ and $8$.
Hence, the factor of the polynomial is $(y+p)(y+q)=(y-6)(y+8)$.
Check:-
$=(y-6)(y+8)$
$=y^2+8y-6y-48$
$=y^2+2y-48$
True.
