Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 5 - Solving Systems of Linear Equations - 5.3 - Solving Systems of Linear Equations by Elimination - Exercises - Page 251: 8

Answer

The solution is $(-3,1)$.

Work Step by Step

The given system of equations is $4x-9y=-21$ ...... (1) $-4x-3y=9$ ...... (2) Add equation (1) and (2). $\Rightarrow 4x-9y-4x-3y=-21+9$ Add like terms. $\Rightarrow -12y=-12$ Divide each side by $-12$. $\Rightarrow \frac{-12y}{-12}=\frac{-12}{-12}$ Simplify. $\Rightarrow y=1$ Substitute $1$ for $y$ in equation (1). $\Rightarrow 4x-9(1)=-21$ Simplify. $\Rightarrow 4x-9=-21$ Add $9$ to each side. $\Rightarrow 4x-9+9=-21+9$ Simplify. $\Rightarrow 4x=-12$ Divide each side by $4$. $\Rightarrow \frac{4x}{4}=\frac{-12}{4}$ Simplify. $\Rightarrow x=-3$ Check $(x,y)=(-3,1)$ Equation (1): $\Rightarrow 4x-9y=-21$ $\Rightarrow 4(-3)-9(1)=-21$ $\Rightarrow -12-9=-21$ $\Rightarrow -21=-21$ True. Equation (2): $\Rightarrow -4x-3y=9$ $\Rightarrow -4(-3)-3(1)=9$ $\Rightarrow 12-3=9$ $\Rightarrow 9=9$ True. Hence, the solution is $(-3,1)$.
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