Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 5 - Solving Systems of Linear Equations - 5.3 - Solving Systems of Linear Equations by Elimination - Exercises - Page 251: 11

Answer

The solution is $(1,1)$.

Work Step by Step

The given system of equations is $x+y=2$ ...... (1) $2x+7y=9$ ...... (2) Multiply each side of equation (1) by $-2$. $-2(x+y)=-2(2)$ Simplify. $-2x-2y=-4$ ...... (3) Add equation (2) and (3). $\Rightarrow 2x+7y-2x-2y=9-4$ Add like terms. $\Rightarrow 5y=5$ Divide each side by $5$. $\Rightarrow \frac{5y}{5}=\frac{5}{5}$ Simplify. $\Rightarrow y=1$ Substitute $1$ for $y$ in equation (1). $\Rightarrow x+1=2$ Subtract $1$ from each side. $\Rightarrow x+1-1=2-1$ Simplify. $\Rightarrow x=1$ Check $(x,y)=(1,1)$ Equation (1): $\Rightarrow x+y=2$ $\Rightarrow 1+1=2$ $\Rightarrow 2=2$ True. Equation (2): $\Rightarrow 2x+7y=9$ $\Rightarrow 2(1)+7(1)=9$ $\Rightarrow 2+7=9$ $\Rightarrow 9=9$ True. Hence, the solution is $(1,1)$.
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