Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 5 - Solving Systems of Linear Equations - 5.3 - Solving Systems of Linear Equations by Elimination - Exercises - Page 251: 4

Answer

The solution is $(-3,29)$.

Work Step by Step

The given system of equations is $9x+y=2$ ...... (1) $-4x-y=-17$ ...... (2) Add equation (1) and (2). $\Rightarrow 9x+y-4x-y=2-17$ Add like terms. $\Rightarrow 5x=-15$ Divide each side by $5$. $\Rightarrow \frac{5x}{5}=\frac{-15}{5}$ Simplify. $\Rightarrow x=-3$ Substitute $-3$ for $x$ equation (1). $\Rightarrow 9(-3)+y=2$ Simplify. $\Rightarrow -27+y=2$ Add $27$ to each side. $\Rightarrow -27+y+27=2+27$ Simplify. $\Rightarrow y=29$ Check $(x,y)=(-3,29)$ Equation (1): $\Rightarrow 9x+y=2$ $\Rightarrow 9(-3)+29=2$ $\Rightarrow -27+29=2$ $\Rightarrow 2=2$ True. Equation (2): $\Rightarrow -4x-y=-17$ $\Rightarrow -4(-3)-29=-17$ $\Rightarrow 12-29=-17$ $\Rightarrow -17=-17$ True. Hence, the solution is $(-3,29)$.
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