Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 8 - Review Exercises - Page 617: 66

Answer

$v=-\frac{\sqrt 2}{4}i+\frac{\sqrt 2}{4}j=⟨-\frac{\sqrt 2}{4},-\frac{\sqrt 2}{4}⟩$

Work Step by Step

$v=||v||(cos~θ)i+||v||(sin~θ)j$ $v=\frac{1}{2}(cos~225°)i+\frac{1}{2}(sin~225°)j$ $v=\frac{1}{2}(-\frac{\sqrt 2}{2})i+\frac{1}{2}(-\frac{\sqrt 2}{2})j=-\frac{\sqrt 2}{4}i+\frac{\sqrt 2}{4}j$
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