Answer
$v=-4i+4\sqrt 3j=⟨-4,4\sqrt 3⟩$
Work Step by Step
$v=||v||(cos~θ)i+||v||(sin~θ)j$
$v=8(cos~120°)i+8(sin~120°)j$
$v=8(-\frac{1}{2})i+8(\frac{\sqrt 3}{2})j=-4i+4\sqrt 3j$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 8 - Review Exercises - Page 617: 65
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