Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 6 - 6.6 - Inverse Trigonometric Functions - 6.6 Exercises - Page 485: 72

Answer

$$\sqrt{1-\left(\frac{x-h}{r}\right)^2}$$

Work Step by Step

By definition: $$ y=\arcsin \left(\frac{x-h}{r}\right) $$ is a number such that: $$ \sin y=\frac{x-h}{r} $$ Then we have that: $$ \sqrt{1-\sin ^{2} y}=\cos y $$ and thus: $$ \cos \left(\arcsin \left(\frac{x-h}{r}\right)\right)=\sqrt{1-\left(\frac{x-h}{r}\right)^{2}} $$
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