Answer
$cot(arctan~x)=\frac{1}{x}$
Work Step by Step
Let $u=arctan~x~~$ (Range: $-\frac{\pi}{2}\lt u\lt\frac{\pi}{2}$)
Then: $x=tan~u$
$cot(arctan~x)=cot~u=\frac{1}{tan~u}=\frac{1}{x}$
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