Answer
$a_3=9$
Work Step by Step
$a_1=16$
$a_n=a_1r^{n-1}$
$a_4=16r^{4-1}$
$\frac{27}{4}=16r^3$
$r^3=\frac{27}{64}$
$r=\sqrt[3] {\frac{27}{64}}=\frac{3}{4}$
$a_3=16(\frac{3}{4})^{3-1}=16·\frac{9}{16}=9$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 11 - 11.3 - Geometric Sequences and Series - 11.3 Exercises - Page 795: 43
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