Answer
$a_{12}=-\frac{2}{59049}$
Work Step by Step
$a_n=a_1r^{n-1}$
$a_1=6,~~r=-\frac{1}{3}$
$a_{12}=6(-\frac{1}{3})^{12-1}=6(-\frac{1}{3})^{11}=6(-\frac{1}{177147})=-\frac{2}{59049}$
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