Answer
$a_4=e^{-3x}=\frac{1}{e^{3x}}$
Work Step by Step
$a_n=a_1r^{n-1}$
$a_1=1,~~r=e^{-x}$
$a_4=1(e^{-x})^{4-1}=1(e^{-x})^3=e^{-3x}$
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