Answer
$a_{10}=\frac{1}{128}$
Work Step by Step
$a_n=a_1r^{n-1}$
$a_1=4,~~r=\frac{1}{2}$
$a_{10}=4(\frac{1}{2})^{10-1}=4(\frac{1}{2})^9=4.\frac{1}{512}=\frac{1}{128}$
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