Answer
$a_n= \frac{9}{2}(2)^n$
Work Step by Step
$a_1=9$
$r=\frac{a_2}{a_1}=\frac{a_3}{a_2}$
$r=\frac{18}{9}=\frac{36}{18}=2$
$a_n=a_1r^{n-1}$
$a_n=9(2)^{n-1}=9(2)^n(2^{-1})=9(2)^n\frac{1}{2}=\frac{9}{2}(2)^n$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 11 - 11.3 - Geometric Sequences and Series - 11.3 Exercises - Page 795: 35
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