Answer
$a_1=6$
$a_2=-\frac{3}{2}$
$a_3=\frac{3}{8}$
$a_4=-\frac{3}{32}$
$a_5=\frac{3}{128}$
Work Step by Step
$a_n=a_1r^{n-1}$
$a_1=6,~~r=-\frac{1}{4}$
$a_2=6(\frac{1}{4})^{2-1}=6(-\frac{1}{4})^1=-\frac{6}{4}=-\frac{3}{2}$
$a_3=6(\frac{1}{4})^{3-1}=6(-\frac{1}{4})^2=\frac{6}{16}=\frac{3}{8}$
$a_4=6(\frac{1}{4})^{4-1}=6(-\frac{1}{4})^3=-\frac{6}{64}=-\frac{3}{32}$
$a_5=6(\frac{1}{4})^{5-1}=6(-\frac{1}{4})^4=\frac{6}{256}=\frac{3}{128}$
