Answer
$a_n=-\frac{5}{2}(-2)^n$
Work Step by Step
$a_1=5$
$r=\frac{a_2}{a_1}=\frac{a_3}{a_2}$
$r=\frac{-10}{5}=\frac{20}{-10}=-2$
$a_n=a_1r^{n-1}$
$a_n=5(-2)^{n-1}=5(-2)^n(-2)^{-1}=5(-2)^n(-\frac{1}{2})=-\frac{5}{2}(-2)^n$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 11 - 11.3 - Geometric Sequences and Series - 11.3 Exercises - Page 795: 36
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